forked from Imagelibrary/binutils-gdb
Make "ptype INTERNAL_FUNCTION" in Ada print like other languages
Currently, printing the type of an internal function in Ada shows
double <>s, like:
(gdb) with language ada -- ptype $_isvoid
type = <<internal function>>
while all other languages print it with a single <>, like:
(gdb) with language c -- ptype $_isvoid
type = <internal function>
I don't think there's a reason that Ada needs to be different. We
currently print the double <>s because we take this path in
ada_print_type:
switch (type->code ())
{
default:
gdb_printf (stream, "<");
c_print_type (type, "", stream, show, level, language_ada, flags);
gdb_printf (stream, ">");
break;
... and the type's name already has the <>s.
Fix this by simply adding an early check for
TYPE_CODE_INTERNAL_FUNCTION.
Approved-By: Andrew Burgess <aburgess@redhat.com>
Approved-By: Tom Tromey <tom@tromey.com>
Change-Id: Ic2b6527b9240a367471431023f6e27e6daed5501
Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=30105
This commit is contained in:
@@ -941,6 +941,13 @@ ada_print_type (struct type *type0, const char *varstring,
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struct ui_file *stream, int show, int level,
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const struct type_print_options *flags)
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{
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if (type0->code () == TYPE_CODE_INTERNAL_FUNCTION)
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{
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c_print_type (type0, "", stream, show, level,
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language_ada, flags);
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return;
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}
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struct type *type = ada_check_typedef (ada_get_base_type (type0));
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/* If we can decode the original type name, use it. However, there
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are cases where the original type is an internally-generated type
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@@ -29,8 +29,6 @@ proc test_ptype_internal_function {} {
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if {$lang == "unknown"} {
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gdb_test "ptype \$_isvoid" \
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"expression parsing not implemented for language \"Unknown\""
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} elseif {$lang == "ada"} {
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gdb_test "ptype \$_isvoid" "<<internal function>>"
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} else {
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gdb_test "ptype \$_isvoid" "<internal function>"
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}
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