forked from Imagelibrary/binutils-gdb
Fortran arrays might have negative bounds. Take this into consideration when evaluating dynamic bound properties. Bernhard Heckel <bernhard.heckel@intel.com> gdb/Changelog: * gdbtypes.c (resolve_dynamic_range): Call dwarf2_evaluate_property_signed to resolve dynamic bounds. gdb/Testsuite/Changelog: * gdb.fortran/vla.f90: Extend by an array with negative bounds. * gdb/testsuite/gdb.fortran/vla-sizeof.exp: Test array with negative bounds. * gdb/testsuite/gdb.fortran/vla-ptype.exp: Test array with negative bounds. Change-Id: Idb35164f72c95a1daafe5db0c0855d742bea5ea7
68 lines
1.9 KiB
Fortran
68 lines
1.9 KiB
Fortran
! Copyright 2015-2016 Free Software Foundation, Inc.
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!
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! This program is free software; you can redistribute it and/or modify
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! it under the terms of the GNU General Public License as published by
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! the Free Software Foundation; either version 3 of the License, or
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! (at your option) any later version.
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!
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! This program is distributed in the hope that it will be useful,
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! but WITHOUT ANY WARRANTY; without even the implied warranty of
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! MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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! GNU General Public License for more details.
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!
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! You should have received a copy of the GNU General Public License
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! along with this program. If not, see <http://www.gnu.org/licenses/>.
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program vla
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real, target, allocatable :: vla1 (:, :, :)
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real, target, allocatable :: vla2 (:, :, :)
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real, target, allocatable :: vla3 (:, :)
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real, pointer :: pvla (:, :, :)
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logical :: l
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nullify(pvla)
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allocate (vla1 (10,10,10)) ! vla1-init
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l = allocated(vla1)
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allocate (vla2 (1:7,42:50,13:35)) ! vla1-allocated
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l = allocated(vla2)
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vla1(:, :, :) = 1311 ! vla2-allocated
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vla1(3, 6, 9) = 42
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vla1(1, 3, 8) = 1001
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vla1(6, 2, 7) = 13
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vla2(:, :, :) = 1311 ! vla1-filled
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vla2(5, 45, 20) = 42
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pvla => vla1 ! vla2-filled
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l = associated(pvla)
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pvla => vla2 ! pvla-associated
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l = associated(pvla)
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pvla(5, 45, 20) = 1
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pvla(7, 45, 14) = 2
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pvla => null() ! pvla-re-associated
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l = associated(pvla)
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deallocate (vla1) ! pvla-deassociated
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l = allocated(vla1)
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deallocate (vla2) ! vla1-deallocated
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l = allocated(vla2)
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allocate (vla3 (2,2)) ! vla2-deallocated
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vla3(:,:) = 13
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allocate (vla1 (-2:1, -5:4, -3:-1))
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l = allocated(vla1)
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vla1(:, :, :) = 1
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vla1(-2, -3, -1) = -231
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deallocate (vla1) ! vla1-neg-bounds
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l = allocated(vla1)
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end program vla
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