Refine Ada overload matching

Currently, the overload handling in Ada assumes that any two array
types are compatible.  However, this is obviously untrue, and a user
reported an oddity where comparing two Ada strings resulted in a call
to the "=" function for packed boolean arrays.

This patch improves the situation somewhat, by requiring that the two
arrays have the same arity and compatible base element types.  This is
still over-broad, but it seems safe and is better than the status quo.
This commit is contained in:
Tom Tromey
2023-11-28 14:26:56 -07:00
parent 1414fbf941
commit d56fdf1b97
3 changed files with 108 additions and 11 deletions

View File

@@ -3930,9 +3930,35 @@ ada_resolve_variable (struct symbol *sym, const struct block *block,
return candidates[i];
}
/* Return non-zero if formal type FTYPE matches actual type ATYPE. */
/* The term "match" here is rather loose. The match is heuristic and
liberal. */
static bool ada_type_match (struct type *ftype, struct type *atype);
/* Helper for ada_type_match that checks that two array types are
compatible. As with that function, FTYPE is the formal type and
ATYPE is the actual type. */
static bool
ada_type_match_arrays (struct type *ftype, struct type *atype)
{
if (ftype->code () != TYPE_CODE_ARRAY
&& !ada_is_array_descriptor_type (ftype))
return false;
if (atype->code () != TYPE_CODE_ARRAY
&& !ada_is_array_descriptor_type (atype))
return false;
if (ada_array_arity (ftype) != ada_array_arity (atype))
return false;
struct type *f_elt_type = ada_array_element_type (ftype, -1);
struct type *a_elt_type = ada_array_element_type (atype, -1);
return ada_type_match (f_elt_type, a_elt_type);
}
/* Return non-zero if formal type FTYPE matches actual type ATYPE.
The term "match" here is rather loose. The match is heuristic and
liberal -- while it tries to reject matches that are obviously
incorrect, it may still let through some that do not strictly
correspond to Ada rules. */
static bool
ada_type_match (struct type *ftype, struct type *atype)
@@ -3970,18 +3996,15 @@ ada_type_match (struct type *ftype, struct type *atype)
return false;
}
case TYPE_CODE_ARRAY:
return (atype->code () == TYPE_CODE_ARRAY
|| ada_is_array_descriptor_type (atype));
case TYPE_CODE_STRUCT:
if (ada_is_array_descriptor_type (ftype))
return (atype->code () == TYPE_CODE_ARRAY
|| ada_is_array_descriptor_type (atype));
else
if (!ada_is_array_descriptor_type (ftype))
return (atype->code () == TYPE_CODE_STRUCT
&& !ada_is_array_descriptor_type (atype));
[[fallthrough]];
case TYPE_CODE_ARRAY:
return ada_type_match_arrays (ftype, atype);
case TYPE_CODE_UNION:
case TYPE_CODE_FLT:
return (atype->code () == ftype->code ());