forked from Imagelibrary/binutils-gdb
Fix accessing a method's fields from Python
Considering this example:
struct C
{
int func() { return 1; }
} c;
int main()
{
return c.func();
}
Accessing the fields of C::func, when requesting the function by its
type, works:
(gdb) py print(gdb.parse_and_eval('C::func').type.fields()[0].type)
C * const
But when trying to do the same via a class instance, it fails:
(gdb) py print(gdb.parse_and_eval('c')['func'].type.fields()[0].type)
Traceback (most recent call last):
File "<string>", line 1, in <module>
TypeError: Type is not a structure, union, enum, or function type.
Error while executing Python code.
The difference is that in the former the function type is TYPE_CODE_FUNC:
(gdb) py print(gdb.parse_and_eval('C::func').type.code == gdb.TYPE_CODE_FUNC)
True
And in the latter the function type is TYPE_CODE_METHOD:
(gdb) py print(gdb.parse_and_eval('c')['func'].type.code == gdb.TYPE_CODE_METHOD)
True
So this adds the functionality for TYPE_CODE_METHOD as well.
gdb/ChangeLog:
2020-12-18 Hannes Domani <ssbssa@yahoo.de>
* python/py-type.c (typy_get_composite): Add TYPE_CODE_METHOD.
gdb/testsuite/ChangeLog:
2020-12-18 Hannes Domani <ssbssa@yahoo.de>
* gdb.python/py-type.exp: Add tests for TYPE_CODE_METHOD.
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@@ -471,6 +471,7 @@ typy_get_composite (struct type *type)
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if (type->code () != TYPE_CODE_STRUCT
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&& type->code () != TYPE_CODE_UNION
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&& type->code () != TYPE_CODE_ENUM
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&& type->code () != TYPE_CODE_METHOD
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&& type->code () != TYPE_CODE_FUNC)
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{
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PyErr_SetString (PyExc_TypeError,
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