[gdb/exp] Fix printing of type of optimized out vla

Consider this snippet from gcc/testsuite/gcc.dg/guality/vla-1.c:
...
int __attribute__((noinline))
f1 (int i)
{
  char a[i + 1];
  a[0] = 5;             /* { dg-final { gdb-test .+1 "i" "5" } } */
  return a[0];          /* { dg-final { gdb-test . "sizeof (a)" "6" } } */
}
...

When we compile the test-case with -O1 -g, and query the size of optimized
out vla 'a', we get:
...
$ ./gdb -batch -ex "b f1" -ex "r" -ex "p sizeof (a)" vla-1.exe
Breakpoint 1 at 0x4004a8: file vla-1.c, line 17.

Breakpoint 1, f1 (i=i@entry=5) at vla-1.c:17
17        return a[0];
$1 = 0
...
while we expect a size of '6'.

The problem is that default_read_var_value does not resolve the dynamic type
of a variable if the variable is optimized out.

This patch fixes that, and consequently gdb prints '6', as expected.

Tested on x86_64-linux.

2018-07-18  Tom de Vries  <tdevries@suse.de>

	* findvar.c (default_read_var_value): Also resolve dynamic type for
	LOC_OPTIMIZED_OUT vars.

	* gdb.base/vla-optimized-out.c: New test.
	* gdb.base/vla-optimized-out.exp: New file.
This commit is contained in:
Tom de Vries
2018-07-03 11:06:45 +02:00
parent 6592ceed48
commit 42dc7699a2
5 changed files with 86 additions and 0 deletions

View File

@@ -789,6 +789,8 @@ default_read_var_value (struct symbol *var, const struct block *var_block,
break;
case LOC_OPTIMIZED_OUT:
if (is_dynamic_type (type))
type = resolve_dynamic_type (type, NULL, /* Unused address. */ 0);
return allocate_optimized_out_value (type);
default: