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gdb: Use c++17 std::make_unique instead of gdb::make_unique

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gdb::make_unique is a wrapper around std::make_unique when compiled with
c++17.  Now that 17 is required, use std::make_unique directly in the
codebase, and remove gdb::make_unique.

Change-Id: I80b615e46e4b7c097f09d78e579a9bdce00254ab
This commit is contained in:
Lancelot Six
2023-09-14 11:13:24 +00:00
parent a6b89d38e2
commit e7b38ccb82
20 changed files with 41 additions and 37 deletions
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3
gdb/cp-support.c
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@@ -44,6 +44,7 @@
#include "run-on-main-thread.h"
#include "typeprint.h"
#include "inferior.h"
#include <memory>
#define d_left(dc) (dc)->u.s_binary.left
#define d_right(dc) (dc)->u.s_binary.right
@@ -675,7 +676,7 @@ mangled_name_to_comp (const char *mangled_name, int options,
options, memory);
if (ret)
{
auto info = gdb::make_unique<demangle_parse_info> ();
auto info = std::make_unique<demangle_parse_info> ();
info->tree = ret;
*demangled_p = NULL;
return info;