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Fix casting in-memory values of primitive types to const reference
It's currently not possible to cast an in-memory value of a primitive
type to const reference:
```
(gdb) p Q.id
$1 = 42
(gdb) p (int&)Q.id
$2 = (int &) @0x22fd0c: 42
(gdb) p (const int&)Q.id
Attempt to take address of value not located in memory.
```
And if in a function call an argument needs the same kind of casting,
it also doesn't work:
```
(gdb) l f3
39 int f3(const int &i)
40 {
41 return i;
42 }
(gdb) p f3(Q.id)
Attempt to take address of value not located in memory.
```
It's because when the constness of the type changes in a call to
value_cast, a new not_lval value is allocated, which doesn't exist
in the target memory.
Fixed by ignoring const/volatile/restrict qualifications in
value_cast when comparing cast type to original type, so the new
value will point to the same location as the original value:
```
(gdb) p (int&)i
$2 = (int &) @0x39f72c: 1
(gdb) p (const int&)i
$3 = (const int &) @0x39f72c: 1
(gdb) p f3(Q.id)
$4 = 42
```
Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=19423
Approved-By: Tom Tromey <tom@tromey.com>
This commit is contained in:
@@ -180,6 +180,9 @@ gdb_test "print (unsigned long long) (LeftRight *) (Right *) &gd == gd_value" \
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gdb_test "print (unsigned long long) (LeftRight *) (Right *) r_value == gd_value" \
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gdb_test "print (unsigned long long) (LeftRight *) (Right *) r_value == gd_value" \
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" = true"
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" = true"
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gdb_test "print (const int &) gd.left" \
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" = \\(const int \\&\\) @$nonzero_hex: 23"
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gdb_test "print reinterpret_cast<LeftRight *>(l) == lr_l" " = true"
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gdb_test "print reinterpret_cast<LeftRight *>(l) == lr_l" " = true"
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gdb_test "print reinterpret_cast<LeftRight *>(r) == lr_r" " = true"
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gdb_test "print reinterpret_cast<LeftRight *>(r) == lr_r" " = true"
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gdb_test "print reinterpret_cast<Left *>(lr) == l_lr" " = true"
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gdb_test "print reinterpret_cast<Left *>(lr) == l_lr" " = true"
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@@ -36,6 +36,11 @@ int f2(Child& C)
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return f1(C); /* Set breakpoint marker2 here. */
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return f1(C); /* Set breakpoint marker2 here. */
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}
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}
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int f3(const int &i)
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{
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return i;
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}
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struct OtherParent {
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struct OtherParent {
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OtherParent (int other_id0) : other_id(other_id0) { }
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OtherParent (int other_id0) : other_id(other_id0) { }
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int other_id;
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int other_id;
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@@ -64,6 +69,7 @@ int main(void)
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f2(Q);
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f2(Q);
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f2(QR);
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f2(QR);
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f3(Q.id);
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MultiChild MQ(53);
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MultiChild MQ(53);
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MultiChild& MQR = MQ;
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MultiChild& MQR = MQ;
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@@ -62,3 +62,4 @@ gdb_test "print mf2(MQ)" ".* = 106"
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gdb_test "print f1(MQR)" ".* = 53"
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gdb_test "print f1(MQR)" ".* = 53"
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gdb_test "print mf1(MQR)" ".* = 106"
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gdb_test "print mf1(MQR)" ".* = 106"
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gdb_test "print mf2(MQR)" ".* = 106"
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gdb_test "print mf2(MQR)" ".* = 106"
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gdb_test "print f3(Q.id)" ".* = 42"
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@@ -411,7 +411,8 @@ value_cast (struct type *type, struct value *arg2)
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In this case we want to preserve the LVAL of ARG2 as this allows the
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In this case we want to preserve the LVAL of ARG2 as this allows the
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resulting value to be used in more places. We do this by calling
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resulting value to be used in more places. We do this by calling
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VALUE_COPY if appropriate. */
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VALUE_COPY if appropriate. */
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if (types_deeply_equal (arg2->type (), type))
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if (types_deeply_equal (make_unqualified_type (arg2->type ()),
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make_unqualified_type (type)))
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{
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{
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/* If the types are exactly equal then we can avoid creating a new
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/* If the types are exactly equal then we can avoid creating a new
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value completely. */
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value completely. */
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